Question

if sin 30 = cos (q-6). where 3q and q-6 are both acute angles. find q

Answer 1

we know sin(90-A) = cos A
So, sin 3q = cos(90- 3q)
Now, cos (90-3q)= cos (q-6)
or,. 90-3q=q-6
or,. 4q=96
or, q=24.

Answer 2

$\boxed{ \underline{ \bf HELLO \: \: DEAR,}}$


$\bf \: sin3q = cos(q - 6)$


$\to \bf cos(90 - 3q) = cos(q - 6) \\ \\ \to \bf 90 - 3q = q - 6 \\ \\ \to \bf 4q = 96 \\ \\ \to \bf q = 24$