Question

If
sin 3A = cos (A-26) then A = _
Free points

Answer 1

Answer:

You should know that , cos(x)=sin(90−x)

hence cos(A−26)=sin(90−A+26)

=sin(116−A)

Now, since 3A is acute,

Hence A is also acute and hence we can directly remove sin function.

$$sin3A = sin(116-A) $

3A=116−A

4A=116

Hence A=29

Answer 2

Answer:

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