If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A.
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hii dood answer is down
Step-by-step explanation:
sin 3A=cos(A-26)
cos(90-3A)=cos(A-26)
both cos get cancels
remaining
90-3A=A-26
90+26=A+3A
116=4A
A=116/4
A=29
hope this may help you
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