In ΔPQR, right-angled at Q, PQ = 3 cm and PR = 6 cm. Determine ∠P and ∠R.
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∠P = 60° and ∠R = 30°
Step-by-step explanation:
Given: In ΔPQR, right-angled at Q, PQ = 3 cm and PR = 6 cm
Find:∠P and ∠R.
Solution:
In ΔPQR, ∠Q = 90°
So PR is the hypotenuse = 6cm
If ∠R = θ, then PQ is the opposite and QR is the adjacent.
QR = √6² - 3² = √36 - 9 = √27 = 3√3
Sin R = PQ / hypotenuse = 3/6 = 1/2
Therefore ∠R = 30°
Sin P = QR / hypotenuse = 3√3/ 6 = √3 /2
∠P = 60°
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