Question

If sin 3A = cos (A - 6) where 3A and (A - 6) are acute angles, Find the value of A.

Answer 1

Heyy mate ❤✌✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️

Sin 3A = Cos ( A - 6)

Sin 3A = Sin [ 90 - ( A-6)]

3A = 90 - A + 6

4A = 96

A = 24.
✔✔✔✔

Answer 2

✨✨❤️hey mate ❤️✨✨
❤️❤️here is your answer ❤️❤️

SinA = cos(A - 6) where 3A and (A - 6).are acute angle.
Find the value of A =??

Hence:-
Sin3A= cos(A- 6)
✨✨we can write Sin3A as :-
✨✨❤️cos(90- 3A) ✨✨❤️❤️

Then put:-
Cos(90- 3A) = cos(A- 6)
✨ (90- 3A) = (A- 6)
90 +6 =A+ 3A
✨ 96 = 4A
✨ A= 96/4
❤️ A = 24✨✨

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