Question

If sin (3x+2y)=1 and cos(3x-2y)=_/3/2 then find the value of x and y

Answer 1

we know that sin 90° = 1 and cos 30°=√3/2 so
3x+2y=90 & 3x-2y =30
on adding we get
6x=120
x=20°
replacing x in 3x+2y=90 we get y=15°

Answer 2

3x +2y=90

3x-2y=30

6x=120

X=20

And

Y=15