Math, asked by bryanmatthew, 8 months ago

If sin(3x−3y+z)=0, find the first partial derivatives ∂z/∂x and ∂z/∂y

at the point (0, 0, 0).

A. ∂z/∂x(0,0)=

B. ∂z/∂y(0,0)=

Answers

Answered by manishdevda1234
0

Answer:

sorry I didn't no answer

Step-by-step explanation:

sorry I didn't no longer

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