If sin(3x)=cos(x-26) find x ?
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Answered by
8
Sin3x = Cos(x–26)
Cos(90–3x) = cos(x–26)
90–3x = x–26
4x = 116
X = 116/4 = 29
Cos(90–3x) = cos(x–26)
90–3x = x–26
4x = 116
X = 116/4 = 29
Answered by
6
sin(3x) = cos(90-x+26)
sin(3x) =sin(116-x)
3x +x = 116
4x =116
x= 116/4 = 29
sin(3x) =sin(116-x)
3x +x = 116
4x =116
x= 116/4 = 29
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