Question

If sin^4 theta + sin^2 theta =1, then show that the value of cot^4 theta + cot^2 theta is 1​

Answer 1

Answer:

Cos^4Ø + Sin^2Ø = 1

Step-by-step explanation:

Given: Sin^4 + Sin^2 = 1

(SinØ)^4 + (SinØ)^2 = 1

[Cos(90-Ø)]^4 + [Cos(90-Ø)]^2 = 1 ___ `.` Cos(90-Ø) = SinØ

Put 90 - Ø = P

.'. Cos^4 P + Cos^2 P = 1

Hence proved