Question

If sin θ = 40/41, then cotθ is

Answer 1

Step-by-step explanation:

Since Sin B = 40/41,

Let's find the value of the base, =

$\sqrt{ {41}^{2} - {40}^{2} } \\ \sqrt{1681 - 1600} \\ = \sqrt{81} \\ = 9 \: cm$

Then, Cot B= Adjacent side/ Opposite side,

= 9/40.

NOW, THAT'S THE CORRECT ANSWER.

Answer 2

Step-by-step explanation:

Since Sin B = 40/41,

Let's find the value of the base=

√41 ² −40²

=√1681-1600

=√81

= 9cm

Then, Cot B= Adjacent side/ Opposite side,

= 9/40.