if sin (60degree-x) =cos(y+60degree) find the value of sin (x-y)
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> sin (60° – x) = cos (y + 60°)
◽⇒ sin (60°–x) = sin (90°– y – 60°) [ ∵ sin (90° – θ) = cos θ)
◽⇒ 60° – x = 90° – y – 60° = 30° – y
◽⇒ x – y = 60° – 30°
◽⇒ x – y = 30°
◽∴ sin (x - y) = sin 30° =1/2
Hence 1/2 is the required solution
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Answered by
1
sin (60° – x) = cos (y + 60°)
sin (60°–x) = sin (90°– y – 60°) [ ∵ sin (90° – θ) = cos θ)
60° – x = 90° – y – 60° = 30° – y
x – y = 60° – 30°
x – y = 30°
∴ sin (x - y) = sin 30° =1/2
Hence 1/2 is the required solution
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