if sin =7÷25 find the value of cos and tan
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4
given sin=7/25
cos^2=1_sin^2
=1-(7/25)^2
=1_49/625
=(625-49)/625
=576/625
cos=root over(576/625)
=24/25
tan=sin/cos
=(7/25)/(24/25)
=7/24
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cos^2=1_sin^2
=1-(7/25)^2
=1_49/625
=(625-49)/625
=576/625
cos=root over(576/625)
=24/25
tan=sin/cos
=(7/25)/(24/25)
=7/24
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Answered by
2
sin=7/25
so sin= opp/ hypo
their for opp=7,hypo= 25
cos=adj / hypo
√oppsquare -√hyposqure= adj square
625-49= adj square
576=adj square
√576=24their for adj = 24
so,cos=24/25
and tan= 7/24
so sin= opp/ hypo
their for opp=7,hypo= 25
cos=adj / hypo
√oppsquare -√hyposqure= adj square
625-49= adj square
576=adj square
√576=24their for adj = 24
so,cos=24/25
and tan= 7/24
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