Question

if sin A=1/√2 and cot B=1,prove that sin (A+B)=1 where A and B are both acute angles?​

Answer 1

Answer:

hope this will help you

Step-by-step explanation:

sinA= 1/√2 when angle is 45° and cotB=1 when angle is 45°

Answer 2

Answer:

a = 45       and       b = 45

Step-by-step explanation:

sin a = 1/√2         and     cot b = 1

sin 45 = 1/ √2       and     cot 45 = 1

from above equations

sin a = sin 45  and     cot b = cot 45

a = 45       and       b = 45

hence a = 45       and       b = 45

and sin (a + b) = sin (45+45) = sin 90 = 1 =R H S

HENCE L H S = R H S

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