Math, asked by ggg63gwghhhehehshhs, 1 year ago

if sin A = 1/2, cos B = 1/2, find A, B and sin 2A

Answers

Answered by rk0435196
9

Answer:

SinA=30○=1/2

So..A=30

Cos B=60○=1/2..

B=60○

Sin 2A=sin2×(30)=60..

Step-by-step explanation:


Answered by wifilethbridge
2

A=30^{\circ}

B = 60^{\circ}

Sin 2A = \frac{\sqrt{3}}{2}

Step-by-step explanation:

Sin A = \frac{1}{2}

A = Sin^{-1}(\frac{1}{2})

A=30^{\circ}

Cos B = \frac{1}{2}\\\\B = Cos^{-1}(\frac{1}{2})\\\\B = 60^{\circ}\\\\

Sin 2A = Sin 2 \times 30 = Sin 60^{\circ} = \frac{\sqrt{3}}{2}

#Learn more:

Sin(A+B) =√3/2, cos(2A-B)= 1/√2

Find A and B

https://brainly.in/question/11918288

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