Question

If sin A=1/2, then find the value ofcos A.
Bhavesh hu​

Answer 1

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SinA=1/2

=P/H

Let the constant be k.

P/H=1k/2k

P=k and H=2k

$\underline{\green {\bold{By\:PGT}}}$

$H^2=P^2+B^2</p><p></p><p>(2k)^2=K^2+B^2</p><p></p><p>4k^2=K^2+B^2</p><p></p><p>4k^2-k^2=B^2</p><p></p><p>K^2 (4-1)=B^2$

$\sqrt {k^2 (3)}=B$

$k \sqrt {3}=B</p><p></p><p>So base =k \sqrt {3}</p><p></p><p>Cos A=B/H</p><p></p><p>\underline{\red {\bold{CosA}}}=k \sqrt {3}/2k</p><p></p><p>=\sqrt {3}/2</p><p></p><p>\mathbb{Be\:Brainly}$

Answer 2

Answer:

I hope this helps for you

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