Math, asked by lb1791200, 10 months ago

If sin A = 1/3 then find the value of 9cot²A + 9.​

Answers

Answered by arinsingh14
1

Answer:

81

Step-by-step explanation:

sin A = 1/3 = P/H

hence,by Pythagoras theorem we find the base

which is equal to

=√8

so, 9cot²A+9

=9cos²A/sin²A + 9

Now put cos²A=(√8/3)² and sin²A=(1/3)²

On solving we get 81 as the answer.

Hope this will helps you.

pls mark it as brainliest.

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