If sin A = 1/3 then find the value of 9cot²A + 9.
Answers
Answered by
1
Answer:
81
Step-by-step explanation:
sin A = 1/3 = P/H
hence,by Pythagoras theorem we find the base
which is equal to
=√8
so, 9cot²A+9
=9cos²A/sin²A + 9
Now put cos²A=(√8/3)² and sin²A=(1/3)²
On solving we get 81 as the answer.
Hope this will helps you.
pls mark it as brainliest.
Similar questions