Question

Suppose that P(A) = 0.3 and P(B) = 0.25 and P(A ∩ B) = 0.1. What is P(B | A(complement))?

Answer 1

P(A')=0.7

P(A'^B)=P(B)-P(A^B)

=0.25-0.1

=0.15

P(B/A')=P(B^A')/P(A')

=0.15/0.7

$\frac{15}{70} = \frac{3}{14} = 0.214$

Answer 2

Answer:

Step-by-step explanation:

Given,

P(A)=0.3

P(B)=0.25

P(A(intersection)B)=0.1

P(A(complement))=1-P(A)

0.7

P(B/A(complement)=P(A intersection B)÷P(A complement)

=0.1/0.7

=1/7