If sin A = 1/√3,
then find the value of...
cosec²A-sec²A/cosec²A+cot²A
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6
Answer:
question ❓❓❓math.......
If tanθ=
7
1
, then
cosec
2
θ+sec
2
θ
cosec
2
θ−sec
2
θ
is equal to
Step-by-step explanation:
answer....math.... ⬇️..
answer...3/4.........
solve.with.exaplamation......
tanθ=
7
1
⇒cotθ=
7
∴sec
2
θ=(1+tan
2
θ)=1+
7
1
=
7
8
and cosec
2
θ=(1+cot
2
θ)=1+7=8.
∴
cosec
2
θ+sec
2
θ
cosec
2
θ−sec
2
θ
=
8+
7
8
8−
7
8
=
64
48
=
4...
3
...hope.its.helps.you.......
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