Question

IF SIN A = 2/3 FIND THE OTHER
SIX TRIGNOMETRIC RATIOS.
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Answer 1

Step-by-step explanation:

cosA=5/3

tanA=2/5

cotA=5/2

secA=3/5

cosecA=3/2

Answer 2

Answer:

cos A=+-(under root 5)/3

sin A=2/3

cosec A=3/2 { because cosec A = 1/sin A}

sec A = +-3/(under root 5)    {because sec A = 1/cos A}

tan A = +-2/ (under root 5)

cot A = +-(under root 5)/2    { because cot A = 1/ tan A}

Step-by-step explanation:

sin^2A+cos^2A = 1

so, in place of sin A we will use 2/3

(2/3)^2+cos^2A =1

cos^2A=1-(4/9)

cos^2A=(5/9)

so, cos A= +-(under root 5)/3

tan A = sin A/cos A

so, tan A = (2/3)/{(+- u.r. 5)/3}

tan A = +- 2/(under root 5)