if sin A=2/3,find the other two ratios, i.e.,cos A and tan A.
Answers
Answered by
2
Step-by-step explanation:
sin²A + cos²A = 1
cos²A = 1 - (2/3)²
= 1- 4/9
cos²A = 5/9
cos A =√5/3
tanA = sinA/cosA
= (2/3) ÷ (√5/3)
= 2/3 x 3/√5
2/√5
Answered by
0
Answer:
Step-by-step explanation:
sin A=opposite / hypotenanse
opposite=2
hypotenanse =3
using pythagorous find other length (adjacent)
2^2+x^2=3^2
4+x^2= 9
x=√5
cos A =adjacent/ hypotenanse
cos A=√5/3
tan A= opposite/adjacent
tan A =2/√5
Similar questions