Question

If sin? A = 2 sin A then find the value of A.​

Answer 1

Answer:

${ \sin {}^{2} (x) } = 2 \sin(x) \\ \\ { \sin {}^{2} (x) } - 2 \sin(x) = 0 \\ \\ \sin(x) ( \sin(x) - 2) = 0 \\ \\ \sin(x) = 0 \: and \: 2 \\ but \: \: \: - 1 \leqslant \sin(x) \leqslant 1 \\ so \\ \sin(x) = 0 \\ \implies \\ x = n\pi ,n \in Z$

x = 0 , if you are in 10th class