Question

If sin A = 24/25, then find sec A.​

Answer 1

Step-by-step explanation:

sinA=p/h

using Pythagoras theorem

b=√25²-24²=√49

b= 7

secA=1/cosA

=h/b

=25/7

Answer 2

given

$sina = \frac{24}{25}$

we have to find secA

we know

$cosa = \sqrt{1 - {sin}^{2} a} \\ \\ = \sqrt{1 - \frac{576}{625} } \\ \\ = \sqrt{ \frac{49}{625} } \\ \\ = \frac{7}{25} \\ \\ \\ so \: \: \: \: \: \: \: \: \: seca = \frac{1}{cosa} \\ \\ = \frac{25}{7}$