Question

If sin(a+2b)=root3/2 and cos(a+4b)=0 a>b and a+4b= 90 find the values of a and b

Answer 1

Answer:

Step-by-step explanation:

---->sin(a+2b) = root3/2

sin(a+2b) = sin60

a+2b = 60

a = 60 - 2b .........(1)

----->cos(a+4b) = 0

cos(a+4b) = cos90

a + 4b = 90

60-2b+4b = 90 [from (1)]

2b = 30

b = 15

--->put b in (1),

a = 60-2b = 60-30 = 30

Answer 2

Answer:

A=30° and B=15°

it may help you...:)