If sin(a+2b)=root3/2 and cos(a+4b)=0 a>b and a+4b= 90 find the values of a and b
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Answered by
5
Answer:
Step-by-step explanation:
---->sin(a+2b) = root3/2
sin(a+2b) = sin60
a+2b = 60
a = 60 - 2b .........(1)
----->cos(a+4b) = 0
cos(a+4b) = cos90
a + 4b = 90
60-2b+4b = 90 [from (1)]
2b = 30
b = 15
--->put b in (1),
a = 60-2b = 60-30 = 30
Answered by
1
Answer:
A=30° and B=15°
it may help you...:)
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