Question

If sin (A+2B)=root3/2 and Cos (A+4B)=0. than find A and B ? ​

Answer 1

Answer:

A = 30°

B = 15°

Step-by-step explanation:

Given Problem:

If sin (A+2B)=root3/2 and Cos (A+4B)=0. than find A and B ? ​

Solution:

To Find:

Value of A and B

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Method:

Given that,

sin(A + 2B) = √3/2

sin(A + 2B) = sin 60°

⇒ A + 2B = 60° -----Equation(1)

Given:

cos(A + 4B) = 0

cos(A + 4B) = cos 90°

⇒ A + 4B = 90° -----Equation(2)

Subtracting (1) from (2), we get

A + 4B - A - 2B = 90° - 60°

2B = 30°

⇒ B = 15°

Putting B = 15° in equation (1), we get

A + 2 (15°) = 60°

A + 30° = 60°

⇒ A = 30°

Answer 2

Answer:

A=30° and B=15°

it may help you....:)