If Sin A/3=1/2 [a+l/a] find sin A .
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Answer:
Given : sinθ=
2
3
Let us first draw a right △ABC,∠B=90 degrees and ∠A=θ
We know that sin θ=
AC
BC
=
Hypotenuse
(perpendicular)
=
2
3
By pythagoras Theorem:
AC
2
=AB
2
+BC
2
or AB
2
=AC
2
−BC
2
=4k
2
−3k
2
=k
2
AB=k
Find other T-rations using their defination:
cos=
AC
AB
=
2
1
tanθ=
AB
BC
=
1
3
cscθ=
sinθ
1
=
3
2
secθ=
cosθ
1
=2
cotθ=
tanθ
1
=
3
1
Step-by-step explanation:
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