if sin A=✓3/2 and cos B=✓3/2, Find the value of tan A - tan B/1+tan A tan B
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sin A=√3/2 then cos A=1/2
implies tanA =√3
similarly tan B =1/√3
then (√3 - 1/√3)/1+ √3 ×1/√3 = (2/√3)/ 2 = 1/√3
implies tanA =√3
similarly tan B =1/√3
then (√3 - 1/√3)/1+ √3 ×1/√3 = (2/√3)/ 2 = 1/√3
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