If sin A = √3 2 and cos B = √3 2 , find the value of tan −tan 1+
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Answer:
If sinA=
2
3
, then
cosA=
1−sin
2
A
=
1−
4
3
=
2
1
tanA=
3
If cosB=
2
3
, then
sinB=
1−cos
2
B
=
1−
4
3
=
2
1
tanB=
3
1
1+tan A tan B
tan A−tan B
=
1+
3
3
1
3
−
3
1
=
1+1
3
3−1
=
2
3
2
=
3
1
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