If sin A =3/4 than Tan A is
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Answer:
sinA=3/4
cosA=√(1-sin²A)
cosA=√(1-9/16) =√7/4
tana=sinA/cosA=3/4 ×4/√7=3/√7
Answered by
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Answer:
sin A =3/4 =P/H
H^2= P ^2+ B^2
(4)^2 = (3)^2 +(B)^2
16 = 9 + ( B)^2
(B)^2 = 16-9
B = sq.root7
Tan A = P/B
= 3/ sq.root 7
=3/ sq.root7 X sq.root7/ sq.root7
= 3sq.root7 /7
HOPE IT HELPS YOU
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