Question

If sin A =3/4 than Tan A is

Answer 1

Answer:

sinA=3/4

cosA=√(1-sin²A)

cosA=√(1-9/16) =√7/4

tana=sinA/cosA=3/4 ×4/√7=3/√7

Answer 2

Answer:

sin A =3/4 =P/H

H^2= P ^2+ B^2

(4)^2 = (3)^2 +(B)^2

16 = 9 + ( B)^2

(B)^2 = 16-9

B = sq.root7

Tan A = P/B

= 3/ sq.root 7

=3/ sq.root7 X sq.root7/ sq.root7

= 3sq.root7 /7

HOPE IT HELPS YOU