if sin a=3/4, then tan a is
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Answer:
sin A = 3/4 = P/H
B = √4²-3² = √7
tanA = P/B = 3/√7 or 3√7/7 (ans)
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sina=O/H
3/4= O/H
3/4= O/H=k (say)
so, O/3=k
H/4=k
so, O=3k
H=4k
Suppose that there is a right angled triangle ABC in which the opposite side is 3k and hypotenuse is 4k
So by Pythagorous theorem in triangle ABC
(H) square = (O) square) + (A) square
so, (4k) square = (3k) square+ (A) square
so 16ksquare- 9k square= A square
so A= root 7k
as tan a = O/A
SO, tan a= 3k/root 7k
so, tan a = 3/root 7
so, tan a= 3 root 7/ 7
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