Question

If sin A = 3/5, prove that tan A + 1/cosA = 2, if A is an acute angle.

Answer 1

Draw right-angled triangle ABC such that Angle C is the right angle.

then,

sin A = BC/AB = 3/5

Let BC = 3 and AB = 5.

by Pythagoras theorem,

AC² = AB² - BC²

= 5² - 3² = 16

⇒AC = √16

AC = 4

Tan A = BC/AC = 3/4 and AC/AB = 4/5

Tan A + 1/cos A = 3/4 + 5/4 = 2

Answer 2

Hey mate....

here's ur answer......

SinA ________. BC = 3
= BC/AB. AB = 5.
= 3/5

Using the Pythagoras theorem....

AC^2 = AB^2 + BC^2

5^2 + 3^2 =

25 - 9 = √16

= 4..

TanA = BC/AC = 3/4

AC/AB = 4/5

TanA + 1/CosA

= 3/4 + 5/4

= 8/4 = 2

Hope it helps ❤️