if sin A=3/5 then find cos A
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Answer:
Then cos a = 5/3.......
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Answer:
sinA=3/5
=p/h
cos =b/h
= 4/3
because by using Pythagoras theorem we get 4 as B(base) and we have given 3 as P (perpendicular) , 5 as H (hypotoneous)
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