the taxi fare of in a city is as follows for first 2 kilometre the fare is rupees 8 for the subsequent distance it is rupees 5 per kilometre taking the distance covered as X and total square recipes variety equation for this information and draw its graph
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Given,Total distance covered= x km=1+(x-1)km
Fare For first kilometre= ₹8
Fare for subsequent distance= ₹5 per km
Fare for next(x-1)km= 5(x-1)
A.T.Q
Total fare= y
8+5(x-1)=y
8+5x-5=y
5x-y+3=0
Which is the required linear equation.
It can also be written as y= 5x+3
When X = 0 ,then Y = 3,When x=1, then y= 5+3=8
When x= 2, then y= 10+3=13
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