If sin A =
3
find value of sin 3A.
Attachments:
Answers
Answered by
1
Step-by-step explanation:
sinA=3/5
√(1-cos²A)=3/5
1-cos²A=9/25
cos²A=1- 9/25
cos²A= 16/25
cosA=4/5
hence cosA=4/5 and sinA=3/5
sin3A
sin(2A+A)
sin2A•cosA+cos2A•sinA
2sinAcosA•cosA+(cos²A-sin²A)sinA
(2•3/5•4/5•4/5)+{(4/5)²-(3/5)²}3/5
(96/125)+{16/25-9/25}3/5
(96/125)+(7/25)3/5
(96/125)+(21/125)
(96+21)/125
117/125
#666
Similar questions