if sin a = 4 ÷ 5 and cos b = 12 ÷ 13 find the value of sin 2a
Answers
Answered by
6
Sina=4/5
Then
For pythagorus therom:-
Cosa=3/5
Sin2a=2 sina cosa
=2.4/5.3/5
Sin2a=24/25
It's your answer...........
Then
For pythagorus therom:-
Cosa=3/5
Sin2a=2 sina cosa
=2.4/5.3/5
Sin2a=24/25
It's your answer...........
Answered by
3
hey friend here is your answer
we know that sin2a=2sina.cosa
putting value of sina&cosa in formula
on finding value of cosA=3/5
so sin2a=2×4/5×3/5
=24/25
Hope it will help you
we know that sin2a=2sina.cosa
putting value of sina&cosa in formula
on finding value of cosA=3/5
so sin2a=2×4/5×3/5
=24/25
Hope it will help you
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