Question

If sin A= 5 by 13 find cos ​

Answer 1

Answer:

12/13

Step-by-step explanation:

Hope the above mentioned one is helpfull

Answer 2

Hello :)

Answer:

cosA = 12/13

Solution:

We know sin@ = (perpendicular or height)/hypotenuse

ATQ,

sinA = 5/13

•°• p = 5 and h = 13

Then, base = b = √[(h)² + (p)²]

b = √[(13)² + (5)²]

b = √(169 - 25)

b = √(144)

b = 12

And cos@ = b/h

•°• cosA = 12/13

__________

Hope it helps :)