If sin (a-b) =0 cos (a+b)=0,0°
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Explanation:
sin (a-b)=sin (0)
bcz.sin0=0
a - b = 0 ...Equation I
Cos (a+b)=cos ( 90 )
be coz cos ( 90 ) = 0
a + b = 1 ...Equation ii
solve both the equations we have
2a = 1
a = 1÷2
and b = 1÷2
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