If sin (A-B) =1/2 and cos (A+B)=1/2 then find A and B
Answers
Answered by
0
Answer:
sin(A−B)=
2
1
⇒sin(A−B)=30
o
[∵sin30
o
=
2
1
]
On equating both sides
A−B=30
o
...(1)
cos(A+B)=
2
1
⇒cos(A−B)=cos(60
o
)[∵cos(60
o
)=
2
1
]
On equating both sides
A+B=60
o
..(2)
Adding (1) and (2)
2A=90
o
⇒A=45
o
Putting value of A in (i)
45
o
+B=60
o
⇒B=15
o
Hence A=45
o
; B=15
o
Step-by-step explanation:
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Answered by
0
Answer:
a = 45 and b = 15
Step-by-step explanation:
sin (a-b) = 1/2
we know that sin 30 = 1/2
Therefore, a-b = 30
a = 30+b----- equation 1
now,
cos(a+b) = 1/2
we know that cos 60 = 1/2
Therefore, a+b = 60
putting the value of a from equation 1
30+b+b = 60
30+2b =60
2b=30
b=30/2 = 15
a+b = 60
a+15 = 60
a = 60-15=45
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