Question

if sin(A+B)=1/2 and cos(A+B)=√3/2 find A and B​

Answer 1

Answer:

The values of both A and B are 0 or the question you have put is bot crrct...

Plz thank me....

Answer 2

Correct question:-

Sin ( A + B) = $\dfrac{1}{2}$

Cos (A - B) = $\dfrac{\sqrt{3}}{2}$

To find :-

The value of A and B.

Answer :-

A = 30°

B = 0°

Solution :-

In Trignometric ratio of angels

$Sin\dfrac{1}{2}= 30°$

$Cos \dfrac{\sqrt{3}}{3}= 30°$

Now,

In place of Sin1/2 and Cos √3/2 we can write 30° .

$Sin(A + B) = sin30° \\ Cos(A - B) = Cos 30°$

$A + B = 30° -----eq. 1\\ A - B = 30°-------eq.2$

Now add eq. 1 and 2.

$A + A + B - B = 30° +30°$

$2A = 60°$

$A = 30°$

put the value of A in equation 1.

$B = 0°$