Math, asked by purnimakushre, 10 months ago

if sin (A-B) =1/2 and cot (A+B)=1/2 then find the value of a and b

Answers

Answered by hajrakhalid1112
0

Answer:

Step-by-step explanation:

sinA-B= 1/2

=> sin A-B =sin 30°

=>. A-B=30°......(I)

also,. cos A+B=1/2

=>cos A+B=cos 60°

=> A+B=60°.......(ii)

by adding (I) and (ii),we get...

2A=90°

=>A= 45°{answer}

putting the value of A in (ii),we get...

45°+B=60°

=>B=60°-45°

=>B=15°{answer}

hence the value of A and B are 45°and 15° respectively.

Answered by kavyasaxena106
1

Answer:

A=45

b=15

Step-by-step explanation:

Sin A-B=1/2. (1/2=sin30)

Sin A-B=sin 30

A-B=30........1

cos A+B=cos 60

A+B=60.....2

adding 1 and 2

2A=90

A=45

putting the value of A in E--1

45-B=30

45-30=B

15=B

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