if sin (A+B)=1 and cos ( A-B) =root 3/2.find the A and B
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Answer: sin(A+B)=1
cos(A-B)=√3/2
We know sin-¹ =90
A+B=9 _ _ _ _(1)
cos (A-B)=root 3/2
A-B=cos-¹ root 3/2
We know cos-¹ root 3/2=30
A-B=30 _ _ _ _ _ (2)
Solve (1) & (2)
A+B=90
A-B=30 add
2A=120
A= 60
B= 30 (ans.)
Step-by-step explanation:
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