Question

if sin (a+b)=1 and cos(a-b)=root 3by2 then find vaule of a and b​

Answer 1

Answer:

Given sin(A+B)=1

⇒sin(A+B)=sin90°

(∵sin90°=1)

⇒A+B=90° …………(1)

Again, cos(A−B)= 3/2

⇒cos(A−B)=cos30°

(∵cos30 °=3/2)

⇒A−B=30° …………(2)

Adding (1)+(2)

A+B+A−B=90 +30

⇒2A=120°

⇒A=120/2

⇒A=60 °

Putting A=60°

in equation-(2) we get

A−B=30°

⇒60°

−B=30°

⇒60 °

−30 °=B

⇒B=30°

∴A=60°

;B=30°

now please mark me as a brainliest and follow me please please please please

Answer 2

Answer:

a+b)=1 and cos(a-b)=root 3by2 then find vaule of a and

Step-by-step explanation:

a+b)=1 and cos(a-b)=root 3by2 then find vaule of a and