Question

if sin (a+b)=1 and cos (a-b) = root3/2, 0<a+b<90,a>b find a and b

Answer 1

I hope this will help you

Answer 2

Given That:
sin (a+b) = 1
cos (a-b) = √3/2
(a+b) is between 0° & 90°
a > b

Solution:
We know that Sin 90° = 1 & cos 30° = √3/2

Therefore, we can say that
a+b = 90 .......E1
& a-b = 30 .......E2

To solve, adding E1 & E3, we get
2a = 120
Therefore, a = 60°

Substituting the value of a in E1, we get
60 + b = 90
or b = 30°

Hence, a = 60° & b = 30°