Question

If sin (A+B)=1 and tan(A-B)=1/√3,find the value of tan A+ cot B

Answer 1

Answer:

Step-by-step explanation:

Sin(A+B)=sin90

So A+B=90

Tan(A-B)=tan 30

So A-B=30

Solving the 2 equation we have

A=60 B=30

Now Tan A + Cot B =Tan 60 + Cot 30

=√3+√3

=2√3

Answer 2

Step-by-step explanation:

at first we know A+B=90,thenA_B =30,then adding two equation we get A ,therefore putting A, we get B