Question

if sin (A+B) =1 cos (A-B) =1

Answer 1

sin(A+B)=sin90 then A+B=90
cos(A-B)=cos0 then A-B=0
angle A=45 and B=45

Answer 2

$<b>●•••••••☆Hello User☆•••••••● 《《Here is your answer》》 <hr size = 3 width = 300 color = #000000 ><font color = #000000> ‍‌‌‌ If sin (A+B) =1 sinAcosB+cosAsinB = 1 .......(1) cos (A-B) =1 cosAcosB+sinAsinB = 1 ........(2) Subtracting (1) & (2) we get; (sinAcosB+cosAsinB) - (cosAcosB+sinAsinB) = 0 sinA (cosB - sinB ) - cosA ( cosB - sinB ) = 0 ( sinA - cosA )( cosB - sinB ) = 0 ( sinA - cosA ) = 0 & ( cosB - sinB ) = 0 sinA = cosA & cosB = sinB A = B = 45° </font> <hr size = 3 width = 300 color = #000000 > ●•••••••☆Brainly Star☆•••••••●</b> <b>॥ॐ 卐 ☪ ✝ ॥</b>$