Question

if sin(A+B)=1andcos (A-B)=√3/2 find AandB​

Answer 1

Answer:

Step-by-step explanation:

A+B=x

A-B=y

Sin x =1

A+B =90........( 1)

Cos y=√3/2

Y=30

A-B =30......... (2)

Add (1) +(2)

Give A=60

Put A=60 in.... (2)

To get Back=30

Answer 2

Answer:

A=60 DEGREE , B=30 DEGREE

Step-by-step explanation:

  sin(A+B)=1                    

                                                         

   Cos(A-B)=√3/2                  

   sin(a+b)=sin 90 degree=A+B=90 DEGREE          eq_1

   Cos (A-B) =COS 30 DEGREE

    =(A-B)= 30 DEGREE                    eq_2

      =A =30 Degree +B  

 by putting the value of A in eq _1

   30 degree +B+B =90 DEGREE

   2B=90 DEGREE-30 DEGREE

  2B =60 DEGREE

  B=30 DEGREE

  HENCE, A =60 DEGREE