Math, asked by ruchitpatel7676, 1 year ago

If sin(A+B)=√3/2 and sin(A-B)=1/2 then find values of
A and B

Answers

Answered by aafrin02
19
A + B = 60
A - B = 45

2A = 105
A = 52.5

putting the value of A in eqn 1 st
(52.5 + B) = 60
B = 60 - 52.5
= 7.5
Answered by shreyamsrinivasan
29

Answer: we know that

sin 60=\frac{\sqrt{3} }{2}

and

sin 30=\frac{1}{2}

now a+b=60

     (+)a-b=30

⇒ 2a=90

⇒a=45

substitute value of a in a+b=60

⇒45+b=60

⇒b=15

hope it helps...

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