Math, asked by MOHDAKHIF, 9 months ago

if sin (A+B)=√3/2,sin(A-B)=1/2 then find AB​

Answers

Answered by adityaraut777
3

Answer:

Step-by-step explanation:

sin(A+B)=\sqrt{3} /2       (Given)

We know sinθ=\sqrt{3} /2 when,

θ=60°

So,

A+B=60-------------(1)

sin(A-B)=1/2

we know,

sinθ=1/2 when,

θ=30°

Hence A-B=30------------(2)

Adding equation (1) and (2

A+B=60

A-B=30

So,2A=90,

A=45°

Therefore,

B=60-45=15°

So, AB=45x15=600

Hope it helps you

Answered by shivshankarmishra185
2

Answer:

A = 45 and B = 15 so AB= 15*45= 600

Step-by-step explanation:

here we use trigonometric table we know that sin 60 is equal to root 3.2 so we put value 60 degree in place of a plus b and we also know that sin 30 is 1 upon 2 so be put 30 degree in place of a minus b

Attachments:
Similar questions