If sin(A+B)=sinAcosB+cosAsinB.Find the value of sin75°
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Let A=30°
and B=45°
Sin75°=Sin(30+45)
=Sin30°Cos45°+Cos30°Sin45°
Since,
Sin30°=1/2
Cos30°=√3/2
Sin45°=Cos45°=1/√2
Ans:-(√3 +1)/(2√2) ≈0.966
and B=45°
Sin75°=Sin(30+45)
=Sin30°Cos45°+Cos30°Sin45°
Since,
Sin30°=1/2
Cos30°=√3/2
Sin45°=Cos45°=1/√2
Ans:-(√3 +1)/(2√2) ≈0.966
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