Math, asked by Goutam5776, 1 year ago

If sin(A+B)=sinAcosB+cosAsinB.Find the value of sin75°

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Answered by 129Raj
0
Let A=30°
and B=45°
Sin75°=Sin(30+45)
=Sin30°Cos45°+Cos30°Sin45°
Since,
Sin30°=1/2
Cos30°=√3/2
Sin45°=Cos45°=1/√2
Ans:-(√3 +1)/(2√2) ≈0.966

129Raj: please select as brainlist answers
Answered by Misha05
0

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