if sin =a/b then find cos
NeelamG:
hey friend there is upon b in ans
i write a by mistake
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sin^2x + cos ^2 x=1
cosx=√1-sin^2x
cosx=√1-(a/b)^2
cosx=[√(b^2-a^2)]/b
cosx=√1-sin^2x
cosx=√1-(a/b)^2
cosx=[√(b^2-a^2)]/b
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i hope it will help u....
sorry in ans there is upon b
sorry in ans there is upon b
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