if sin a equal to cos a find the value of 2 x square A + sin square A - 1
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2×sin²A+sin²A-1
=2×cos²A(sin=cos)
and Sin²A-1= Cos²A(Cos²Theta+sin²theta =1)
so 2cos²A+Cos²A
=3cos²A
=2×cos²A(sin=cos)
and Sin²A-1= Cos²A(Cos²Theta+sin²theta =1)
so 2cos²A+Cos²A
=3cos²A
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